Inertia lab report Essay

A Rotational motion audition is the simplest order of governing the Moment of Inertia. Minimum equipment is need to perform this sample. For the purposes of increasing the accuracy of the results, the performance should be repeated three times, qualification our conclusion more than reliable. While core is moving downwards its electric potential energy converts to kinetic. Load is accelerating be bring in weight(Fg=mg) of the agitate is larger than tension on a suck so load is not in equilibrium and by Newtons Second Law (F=ma) resultant ride creates an acceleration. Resultant force basin be calculated by the equation S=0.5at2+ut to attend acceleration and F=ma. String rotates the spindle which rotates the record by creating a ?? tortuousness(T=Fr). Torque hastens the book and it sight be found by ? = ??. To find moment of inaction now T=I? equation is used. 1 system and observation Apparatus 3 varied size books, spindle, ruler, set of weights, stopwatch, sta nd. record book is attached to one end of the spindle and draw sop up with load is attached to the other end. dish aerials weight, diameter and radius ar required to be deliberate in the first place experiment. Length of the string (L), number of loops on the spindle (n) and horizontal outstrip of loops (H) were measured before experiment.Using equation below r is found. ?? = ??????? 2???? Spindle record String Stopwatch Weights Stand later on setting alone the equipment up the experiment starts. The string is then wrapped or so the spindle. measure was measured for load commotion the distance of length of the string. To plot graphical recordical record one over time2 is required to be calculated. 4 different kittyes of the load be used in experiment is repeated 3 times every time mass is changed to make slew ergodic error. After finishing all the experiments on one of the discs other disc is placed and experiment repeats.When all the experiments are done and meas urements are recorded mass against one over time2 is plotted apply results. 3 graphs are going to be plotted for each disc. Gradient of the graph is constant k which we could use to find I using formulae below. When observed the string with vibrating and load was moving a lilliputian which support cause some organized error. While spindle is spinning there is some friction which is neglected and the disc is vibrating while it is spinning which also cause some systematic error. ?? = ???? ? 2???? 2 Results MEASUREMENTS ON THE SPINDLE MEASUREMENTS ON THE dish aerialS n= 8 L= 0. 26m dish aerial 1 (small)DISC 2 (medium) DISC 3 (large) Weight (kg) 0. 314 0. 490 Diameter (m) Radius (m) 0. 1 0. 127 0. 05 0. 0635 0. 696 0. 152 0. 076 H= 0. 026m r= 5. 1410-3 DISC 1 Weight (kg) Time (s) fair(a) Time (s) 1/t? (s-2) K (m s? ) I (kg m2) experimental I (kg m2) notional ?I (kg m2) 0. 1 2. 93 2. 73 2. 62 2. 76 0. 131 0. 15 2 2. 1 2. 23 2. 11 0. 225 1. 439 0. 000346 0. 2 1. 87 1. 85 1. 86 1. 86 0. 287 0. 22 1. 81 1. 74 1. 78 1. 78 0. 317 0. 000393 0. 000047 DISC 2 Weight (kg) Time (s) bonny Time (s) 1/t? (s-2) K (m s? ) I (kg m2) experimental I (kg m2) theoretical ?I (kg m2) 0. 1 6. 49 6. 16 6. 33 6. 33 0. 02500. 15 4. 97 4. 77 509 4. 92 0. 0413 0. 686 0. 000726 0. 000988 0. 000262 3 0. 17 4. 38 4. 97 Z 4. 43 4. 43 0. 0510 0. 20 4. 00 4. 13 4. 08 4. 07 0. 0604 DISC 3 Weight (kg) Time (s) Average Time (s) 1/t? (s-2) K (m s? ) I (kg m2) experimental I (kg m2) theoretical ?I (kg m2) 0. 1 4. 21 4. 13 4. 17 4. 17 0. 0575 0. 15 3. 13 3. 27 3. 00 3. 13 0. 102 0. 290 0. 00172 0. 00201 0. 00029 4 0. 2 2. 73 2. 75 2. 73 2. 74 0. 113 0. 17 3. 03 2. 77 2. 83 2. 9 0. 119 Calculations T=I? -3 T=Fr I = ?? = ???? = ????? = ?????? ? = ?????? ???? ?? ?? ?? ?? 2?? 1 = ?????? ? > 1 =km >k = ????? ??? 2???? ??? 2???? 9. 8x(5.1410? 3 )? I1e= 21. 4390. 26 =0. 000346ms? 9. 8x(5. 1410? 3 )? I2e= 20. 6860. 26 =0. 000726ms? 9. 8x(5. 1410? 3 )? I3e= 20. 2900. 26 =0. 001 72 ms? I1t=0. 50. 0520. 314=0. 000393 ms? I2t=0. 50. 063520. 490=0. 000988 ms? I3t=0. 50. 076020. 696=0. 00201 ms? ?I1=0. 000393-0. 000346=0. 000047 ms? ?I2=0. 000988-0. 000726=0. 000262 ms? ?I3=0. 00201-0. 00172=0. 000290 ms? 5 fallacy Analysis ????? ?? = 2???? ??? ?? 1(2??? +2??? ) ??? +??? 2(?? +?? ) ?? +?? = =? r= 0. 0005+0. 0005 ?r= 0. 26+0. 026 r x5. 1410-3=1. 7910-5 ?s=0. 00192 ?k=0. 176 ?I=1. 7910-50. 001920. 176=6. 0510-9 6 Graphical mold criminal record 1. 1/s? 0. 35 0. 3 y = 1. 439x 0. 25 0. 2 0. 15 0. 1 0. 05 1/t? 0 0 0. 05 0. 1 0. 15 0. 2 0. 25 Weight kg 1/s? 0. 16 Disc 2. 0. 14 y = 0. 686x 0. 12 0. 1 0. 08 0. 06 1/t? 0. 04 0. 02 0 0 0. 05 0. 1 Weight 0. 15 0. 2 0. 25 kg 7 Disc 3. 1/s? 0. 07 0. 06 y = 0. 290x 0. 05 0. 04 0. 03 1/t? 0. 02 0. 01 0 0 0. 05 0. 1 Weight 0. 15 0. 2 0. 25 kg 8 Discussion From the results gained it can be concluded that larger and heavier the disc is greater the moment of inertia of a body. As we can see the side on the graphs are larger at larger discs. From theoretical values which it can be concluded that experiment was right. much time is taken to pass that distance for larger discs because the moment of inertia is bigger so it torque is required to accelerate the disc. However there were some random and systematic errors. One of the most effecting random errors is the human reaction error. It could be rock-bottom by using light opening instead of stop watch. Using more precise equipment for taking measurements of discs and spindle would moderate the error. Masses of the loads are not exact so more accurate loads would decrease the error. Conclusion big and heavier discs have larger moment of inertia so they require more torque to be accelerated.